If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x^2-x-410=0
We add all the numbers together, and all the variables
x^2-1x-410=0
a = 1; b = -1; c = -410;
Δ = b2-4ac
Δ = -12-4·1·(-410)
Δ = 1641
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{1641}}{2*1}=\frac{1-\sqrt{1641}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{1641}}{2*1}=\frac{1+\sqrt{1641}}{2} $
| 14x+10=26x-19 | | -4*(5x-8)=22x-52 | | -3k^2+10k+8=0 | | 9(x-11)`=9` | | x-1/3+2x-3/3=4 | | 2x=5+x=12 | | 3•(x-9)=x-13 | | 5^3x+2=311 | | 2/5+4t/4=5t/8 | | 5^3x+7=311 | | y/3-1/15=2y/9 | | 2x+x/6=13 | | 3x/6=13 | | 8k-13k+10=13k-5 | | 7y^=13y+10 | | 13*1.2-6y=22 | | x*40=700 | | 13x-6*1.2=22 | | (2x)2-3x-4=0 | | (2x)2-3x-7=5 | | 4t-7=t+11 | | (2x)2-3x-7=2x-1 | | 2x+61=11x-2 | | 50-x=23 | | Y=(2x)2-3x-7 | | 7n^2−17n+3=0 | | 7n^2−17n+3= | | 7n^2-17n-8=0 | | 7n^2-10n-8=0 | | 3+(7x-5)=19 | | -19x+10=x-210 | | 3m+10=34m= |